Write a C program for Dynamic Memory Allocation(malloc).
Function Main
Declare N, sum, i as integers
Declare iptr, tmp as integer pointers
Print "Enter value of N [1-10]: "
Read N from user
Allocate memory for iptr with size N * sizeof(int)
If iptr is NULL
Print "Unable to allocate memory space. Program terminated."
Return -1
Print "Enter N integer number(s)"
For i from 0 to N-1
Print "Enter #(i+1): "
Read input and store it in tmp
Add the value of tmp to sum
Print "Sum: ", sum
Free the memory allocated for iptr
End
#include <stdio.h>
int main(void) {
//!ShowMemory(start=1000)
// integer variables
int N = 0;
int sum = 0;
int i;
// integer pointer variables
int *iptr, *tmp;
// take user input
printf("Enter value of N [1-10]: ");
scanf("%d", &N);
// allocate memory
iptr = (int *) malloc (N * sizeof(int));
// check if memory allocated
if (iptr == NULL) {
printf("Unable to allocate memory space. Program terminated.\n");
return -1;
}
// take integers
printf("Enter %d integer number(s)\n", N);
for (i = 0, tmp = iptr; i < N; i++, tmp++) {
printf("Enter #%d: ", (i+1));
scanf("%d", tmp);
// compute the sum
sum += *tmp;
}
// display result
printf("Sum: %d\n", sum);
// free memory location
free(iptr);
return 0;
}
Enter value of N [1-10]: 5
Enter 5 integer number(s)
Enter #1: 10
Enter #2: 20
Enter #3: 30
Enter #4: 40
Enter #5: 50
Sum: 150
More Example:
//Example: 02
#include <stdlib.h>
int main() {
//! showMemory(start=1000)
int * p = malloc(4 * sizeof(int));
int * q = malloc(1 * sizeof(int));
free(q);
int * r = malloc(2 * sizeof(int));
return 0;
}
//Run this code in C Programming Manual Tracing
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